$4x+7y=123$
$-4y^0$
$\int\frac{x-2}{\left(2x+1\right)\left(x^2+2x+2\right)}dx$
$\lim_{x\to\infty}\left(2x^4-x^3\right)$
$-y^2y^2-5xy^3-4y^4+7xy^3-8+x^2y^2$
$\frac{x+1}{x}+1=\frac{x}{x-1}$
$\:2a\:+\:ab$
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