$\int tan^5xsec^8xdx$
$dy=\left(x-3\right)dx$
$\frac{dy}{dx}=3y^2-4y$
$2x^4-7x^3-2x^2+13x-6$
$\left(2x^2+8x-3\right)\cdot\left(x^2-9x+4\right)$
$2\left(0^2+1\right)-3\left(0^2-1\right)$
$7x^2-70xy+175y^2$
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