$7x+1-\left(x^2-4\right)$
$\text{sen}^2a+3=4-\cos^2a$
$\int\left(x\left(x^2-3\right)^5\right)dx$
$10\cdot5+3$
$\left(6xy-y^3\right)dx=\left(3xy^2-4y-3x^2\right)dy$
$-4k+4=40$
$\left(3s^{\frac{1}{2}}\right)^5$
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