$7-7t=28$
$3.25\:x\:10^{-1}$
$\tan^2\left(x-2\right)=3$
$\left(-5xy+3\right)\left(-3-5xy\right)$
$\lim_{x\to0}\left(\frac{5\cdot tan\left(x\right)-5\cdot x}{7\cdot x^2}\right)$
$4-2a+4a+5-7-3a$
$\lim_{x\to\infty}\left(\frac{7x}{x+2}\right)$
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