$x^2+2x+y^2=0$

$\int\:\frac{4t^2+3t-1}{t^3-t^2}dx$

$\int_0^{\frac{5\sqrt{2}}{2}}\left(\frac{11x^2}{\left(25-x^2\right)^{1.5}}\right)dx$

$6\::\:3\:-12\::\:4$

$\frac{4x^2}{25}-\frac{xy}{5}+\frac{y^2}{16}$

$\int\:\left(\frac{3}{2x}-4x^5\right)\left(\frac{6}{5\sqrt[4]{x^3}}+\frac{2}{x^3}\right)dx$

$\frac{3x-1}{5}=\frac{x+11}{2}$