$3x^5-9x^3z^4$
$a\left(x\right)=\:3\cdot2+5x+6$
$\left(w^4-7\right)\left(w^4-6\right)$
$4\left(4+b''\right)$
$3x^2+14x+8$
$\left(\frac{1}{2}a-b\right)^2$
$\frac{x}{2}+\frac{3}{4}$
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