$\lim_{x\to0}\left(1+\frac{x}{2}\right)^{\frac{2}{3x}}$
$\frac{3a+6b^2}{3}$
$\left(z^2\:-\:3w\right)\left(z^2\:+\:3w\right)$
$\left|\left(-3\right)\cdot\left(-2\right)\right|\cdot\left(-4\right)$
$x^7\cdot x^{12}$
$3x^2+4y^2=2x$
$\frac{m^2-4}{5am+10a}$
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