limx→∞(3+64x3x3+83)\lim_{x\to\infty}\left(\sqrt[3]{\frac{3+64x^3}{x^3+8}}\right)x→∞lim(3x3+83+64x3)
sinx=57\sin x=\frac{5}{7}sinx=75
p2−16p^2-16p2−16
2x+4x−3x2x+4x-3x2x+4x−3x
dydx4y2y2−9=x2\frac{dy}{dx}\frac{4y^2}{y^2-9}=x^2dxdyy2−94y2=x2
(+12)−(−7)\left(+12\right)-\left(-7\right)(+12)−(−7)
(xa)2\left(x^a\right)^2(xa)2
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