$\frac{343a^9216b^{15}}{7a^3+6b^5}$
$\frac{x+5}{x-3}=\frac{2}{3}$
$\left(x\frac{1}{3}\right)^2$
$\int_0^4-6e^{7x}dx$
$12a^2-60a+75$
$3^2-10\left(2\right)+\left(-5-7\right)$
$\left(-40\right)\left(12\right)\left(-15\right)\left(-3\right)\left(5\right)\left(2\right)$
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