$\int\left(3x+4\right)^{12}dx$
$\left(2a+5a^2+a^3-3\right)\left(a^3-2a-7\right)$
$\frac{dy}{dx}-\frac{3x^2}{2y}=0$
$4x^2+18x+40$
$\int12x\cdot\cos\left(x\right)dx$
$6k+6=18$
$x^2+4ax$
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