$\frac{1}{2}-\frac{10}{9x}=\frac{4}{9}-\frac{1}{6x}$
$xy^{'\:}+y=xy^2$
$x^2\frac{dy}{dx}-2xy=x^4+3$
$x^3+y^3=4$
$\sqrt[3]{8x^3}$
$\frac{dy}{dx}=\frac{\cos\left(x\right)e^{sin\:\left(x\right)}}{\cos\left(y\right)}$
$2x\:+\:x^2\:-\:5x\:-\:3x^2\:+\:x\:+\:4x^2$
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