$\lim_{x\to\infty}\left(\frac{x}{4}\right)^{\frac{1}{x-4}}$
$4x^2\:-\:8x\:+\:4$
$\frac{p^{-8}}{p^3}$
$\left(a^2\right)^0\left(5x^0\right)$
$\lim_{x\to0}\left(\frac{-2}{-senx+x}\right)$
$2a-3b-6c-3a-11b-3c-5a-3b+4c$
$\left(y^2-6y\right)\cdot\left(3y^2-2y+1\right)$
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