$\frac{2x^3+16^2+32x}{4x^2-64}$

$\lim_{x\to0}\left(\frac{-\tan\left(x\right)\cdot\sin\left(x\right)}{x^2}\right)$

$-1-x=1.2$

$\frac{x^3+6x^3-12x-9}{x+3}$

$11.97+-1h>9.97$

$\frac{\sin\left(x\right)+\sin\left(x\right)\cos\left(x\right)}{\cos\left(x\right)+\cos\left(x\right)\cos\left(x\right)}=\tan\left(x\right)$

$\frac{1}{2}x+4\ge3$