$\frac{27a^3b^2}{3ab^2}$
$\int3x^2\left(x-2x^2\right)dx$
$c^4+8c^2+16$
$\cos\left(7b\right)\sin\left(4b\right)$
$\left(4x-3x^3+2x^2-1\right)\cdot\left(4x+2x^2+3\right)$
$3b^2-24b+48$
$\frac{\frac{1}{3}m}{4}=\frac{3}{\frac{1}{4}}$
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