$-7-\left(1-8\right)-1$
$\frac{u^2-3u}{7}=0$
$\left(7^2-7^2\ln\left(5x\right)\right)$
$\int\frac{24}{\left(6x-5\right)^5}dx$
$\lim_{x\to\infty}\left(\frac{x^2+x-6}{x^2-4x}\right)^x$
$\int234dx$
$3m^2+30m+75$
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