$3x^3-y+5x=x^2$
$x^2+\left(\frac{1}{x^2}\right)+x^3+\frac{1}{x^3}$
$-4\left(-2r+5\right)$
$\lim_{x\to-3}\left(\frac{x^2-3x+2}{x+3}\right)$
$\int\left(\frac{w^2}{\left(w-6\right)\left(w^2-36\right)}\right)dw$
$\frac{d}{dx}2y^2$
$\frac{d}{dx}\frac{1}{2x-1}$
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