$\int_0^1\left(\frac{e^x}{\left(e^x+a\right)ln\left(e^x+a\right)}\right)dx$

$\frac{1}{e^y}y'\:=-\frac{1}{e^{4x}}$

$8\cdot\frac{6}{8}$

$a=\frac{1}{\cot^2\theta}+\frac{1}{\sec^2\theta}+\frac{1}{\csc^2\theta}$

$13+\left|-1-\left(-1\right)\right|$

$\frac{x^{4}-3^{4}}{x^{2}-3^{2}}$

$\left(2y^3+5\right)^4$