$3a+6$
$\left(x-27\right)^3$
$\left(\frac{1}{4}a-\frac{1}{3}\right)^2$
$-y^2-4y+1-y-3$
$\frac{c+1}{c}=1-\frac{c^2-3c-4}{4c}$
$-6x^2+5x-50$
$\left(x-5\right)^2\ge0$
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