$\frac{dy}{dx}=1+\frac{1}{y^2}$

$\frac{\frac{\left(2x-6\right)}{\left(y\right)}}{\frac{\left(x-3\right)}{y+1}}$

$14d^2+21$

$\frac{1}{16}x^2-\frac{3}{160}x+1$

$\left(3m^4+12\right)\left(3m^4-3\right)$

$\frac{1-\tan\left(36\right)}{1+\tan\left(36\right)}=\tan\left(9\right)$

$\int2x\cos\left(6x\right)dx$