$\sqrt{4x}$
$\left(8x^5+16x^3\right)\left(-x^2-2\right)$
$\frac{dy}{dx}=\sin\left(12x-13\right)$
$\frac{-4x^3+x^2-4}{x+19x-1}$
$\frac{dy}{dx}=x^2-\frac{2}{3}y$
$\int\frac{2x-1}{x^2+4x+3}dx$
$\lim_{x\to-\pi}\left(\frac{9\cos\left(x+9\right)}{\left(x+\pi\right)^2}\right)$
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