$y=\frac{x^2+x-6}{x^2-4}$
$x^2+3x+6=0$
$\frac{1}{5-x},c=1$
$-xy-3xy-2xy-3$
$\left(16xb^2-5xy^3\right)^2$
$\int\left(\frac{y+1}{\left(y^2+1\right)^2}\right)dy$
$\frac{2x^2+4x+5}{\left(x+1\right)^2}$
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