$\left(x^2y^3\right)\left(x^5y^6\right)$
$\left(1+x^2\right)\frac{dy}{dx}=x\left(1+y^2\right)$
$\frac{x}{6b^2}\cdot\frac{9b^4x}{2x^3}$
$c^2-12c+36$
$3a^32b^3$
$\sqrt[2]{4}-5$
$1+\infty$
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