$3\left(\frac{2}{3}\right)\:-\:8$
$-4\left(x-2\right)^2+3$
$- 2 x - 10 x ^ { 2 } + 3 ( 5 x ^ { 2 } - 3 x )$
$81+0,003$
$\frac{a^3b^{-4}}{a^{-3}b^2}$
$-x^2-2x+3\ge0$
$-\sqrt{1}+\sqrt{-4-5}$
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