$\frac{1-\sec^2\:x\:}{\:\sec^2x}$
$csc^2\left(x\right)\cdot tan^3\left(x\right)$
$x+xy;\:x=4;\:y=8$
$y'=\left(1+x^2\right)\left(1+y^2\right)$
$25m^{4\:}-16n^4$
$x^2+\frac{x}{2}+3$
$\left(5m^2-n-3mn+mn^3\right)\left(-2m\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!