$1+tan^2\:y$
$\left(9x+4\right)^3$
$\:5\left(a\:-\:2b\right)^2\:-\:2\left(a\:-\:3b\right)^2\:-\:2b\left(b\:-\:4\:a\right)$
$\:x^2\ast\:x^3$
$-7x^2-5+6x+10x^2-8x$
$\frac{\frac{e^{2x}}{1+x^2}}{e^{2x}}$
$-\left(-\left(-14\right)-\left(-20\right)-9\right)$
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