$\:\lim_{x\to-\infty}\left(5x^5-x^2\right)$
$x+9=-4$
$2\sin\left(3\right)=1$
$\lim\:_{x\to\:\frac{x}{4}}\left(\cot\:\left(x\right)^{\tan\:\left(2x\right)}\right)$
$-\left(-75-15\right)-\left(-200-380\right)-\left(420-150\right)$
$\left(b^5\right)\left(b^4\right)\left(b^8\right)$
$2-2x\le9-4x$
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