$-1-2+1$

$\frac{\left(1+cos\:x\right)\left(1-cos\:x\right)}{six\:x}$

$x^2+3x+3$

$\left(3x^{4}-5x^{3}+5x^{2}-2x\right):\left(x^{2}-x+1\right)$

$3\left(-3\left(-4+5x\right)-2x-12\right)$

$\int_4^2\left(3x+6x^5\right)^2dx$

$\left(-\frac{6}{5}a^2b^5c^2\right)\cdot\left(-\frac{1}{10}a^3b^2c^2\right)$