−1m−2 = −6m+3\frac{-1}{m-2}\:=\:\frac{-6}{m+3}m−2−1=m+3−6
(ey−1)dydx=3+8cos(x)\left(e^y-1\right)\frac{dy}{dx}=3+8\cos\left(x\right)(ey−1)dxdy=3+8cos(x)
−7x(2x+1)-7x\left(2x+1\right)−7x(2x+1)
(x−5)(x+1)\left(x-5\right)\left(x+1\right)(x−5)(x+1)
−6−6⋅3-6-6\cdot3−6−6⋅3
sin−1(sin(12))+cos−1(cos(12))\sin^{-1}\left(\sin\left(12\right)\right)+\cos^{-1}\left(\cos\left(12\right)\right)sin−1(sin(12))+cos−1(cos(12))
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