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Exercise

dydx=1−x2+y2−x2y2x2\frac{dy}{dx}=\frac{1-x^2+y^2-x^2y^2}{x^2}

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Final answer to the exercise

y=tan⁡(C0+−x2+1x)y=\tan\left(C_0+\frac{-x^2+1}{x}\right)

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dydx =1−x2+y2−x2y2x2 
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