$\frac{d}{dx}2y^3+4xy+x^2=7$
$\sqrt[3]{64x^6}$
$x^3+5\left(-x+1\right)$
$1-b^5$
$\left(x+1\right)^7$
$cos\:^2x-cos\left(90-x\right).sin\:x=cos2x$
$x^2+12=95$
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