$\frac{x}{4}+\frac{x}{6}$

$2\left(x-1\right)+3=4x-7$

$\left(7g\:+\:1\right)\left(5\right)$

$\lim_{x\to\infty}\left(\frac{sin\left(2x\right)}{sin\left(5x\right)}\right)$

$\frac{1}{4}y'-x^2=0$

$\int\frac{-3x-4}{\left(x+1\right)\left(x+3\right)}dx$

$\int y\sec\left(y\right)dx$