$\frac{\cos\left(x\right)-\cos\left(3x\right)+4\cos\left(x\right)^3}{4\cos\left(x\right)}=1$
$\lim_{x\to0}\left(tan\left(2x\right)^2\right)$
$\sqrt[3]{27w^{21}}$
$8x\le40$
$\left(-12\right)+\left(-18\right)-\left(-1\right)+\left(-7\right)-\left(+28\right)$
$3x^2+4x^2-17x-6$
$36x^2+120x+16$
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