$0.1123\left(5\right)$
$\frac{\frac{11}{3}x+1}{5}>\frac{5}{3}$
$ab^2+a^3b$
$\frac{3x-9}{2x+8}$
$26a-10$
$\:\left(3x+1\right)^2=\left(2x-2\right)^2$
$\int3xe\left(x+5\right)dx$
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