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Exercise

$\frac{dy}{dx}+2y^2=1$

Step-by-step Solution

1

Apply the formula: $a+\frac{b}{c}$$=\frac{b+ac}{c}$, where $a=2y^2$, $b=dy$, $c=dx$, $a+b/c=\frac{dy}{dx}+2y^2$ and $b/c=\frac{dy}{dx}$

$\frac{dy+2y^2dx}{dx}=1$

Final answer to the exercise

$\frac{dy+2y^2dx}{dx}=1$

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