$\int\frac{x^3}{\left(x+3\right)^{\frac{5}{2}}}dx$
$-7=s-1$
$\frac{4a^2b^4-64c^8}{2ab^2+8c^4}$
$\left(\frac{1}{2}x+4\right)\left(\frac{1}{2}+4\right)$
$3x-2>13$
$\left(x+4\right)^{2}+\left(x-3\right)^{2}=\left(x-5\right)^{2}$
$\frac{dy}{dx}=3xlny$
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