$\int\frac{1}{x-h\cdot\sqrt{x}}dx$
$\frac{x^2-8x+15}{\left(x^2-6x+5\right)}$
$\int\frac{\left(4x+6\right)}{\left(x^2+3x-8\right)}dx$
$-3\left(a-2b+c\right)-\left(a-2b+2c\right)$
$\lim_{x\to\infty}\left(\frac{x^3-3x}{x-2}\right)$
$\sqrt{25\cdot\:64}$
$x^2+18x+4=0$
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