$y^2\left(4x^4-12x^3-27x^2-12x-1\right)$
$3x-5\le2x-5$
$6\left(4x+11\right)+2\left(x+8\right)$
$\left(3.7\right)^0$
$xy'+4y=9x^5+2x^3$
$\left(3x\:+\:1\right)\left(3x\:+\:5\right)$
$\frac{dx}{dt}+\frac{x}{20}=6.6$
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