$\frac{dx}{dy}+3xy^3=0\:$
$6x+8x-3x+7x$
$\frac{5x^3-4x^2-3x-1}{x+1}$
$\frac{d^2}{dx^2}\left(e^{-3x}+2x^2\right)$
$144x^2-96x+16$
$\left(5x^2-3y\right)\left(2x^2+y\right)$
$\left(5xy-6\right)\:^3$
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