$x^3-3x\cdot2x^2+3x+5$
$\sqrt[120]{2.7070415}$
$\lim_{x\to2}\left(\frac{x^3+3x^2-x-18}{x-2}\right)$
$\frac{dy}{dx}\left(4x^6y^3+2x^3y-y^7x=10\right)$
$\frac{2}{3}x-4=8$
$-10-\left(-2\right)\left(-1\right)\left(-3\right)$
$7\cdot b=-210$
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