∫x(x2−4)(x+1)dx\int\frac{x}{\left(x^2-4\right)\left(x+1\right)}dx∫(x2−4)(x+1)xdx
∫x(2x+3)12dx\int x\left(2x+3\right)^{12}dx∫x(2x+3)12dx
4x2+9y2+z2−8x−36y+36=04x^2+9y^2+z^2-8x-36y+36=04x2+9y2+z2−8x−36y+36=0
x2+21−10=0x^{2+21-10=0}x2+21−10=0
2x+6>7x−62x+6>7x-62x+6>7x−6
x2+10x−56x^2+10x-56x2+10x−56
3−x<123-x<123−x<12
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