$x^3y^2=6$
$\sqrt{x}^2-2y$
$\lim_{x\to-4}\left(2x^2+5x\right)$
$-a^2b+\frac{3}{11}\:a^3b$
$\frac{3}{4}x-\frac{5}{4}-\frac{2}{5}x+\frac{3}{5}\ge\frac{9}{20}x-\frac{7}{20}$
$-2x^2<4$
$2\left(x+1\right)^2=\:\left(x-1\right)^2$
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