$\frac{3b^3d^2}{6bd^5}^2$
$9x^2+16y^2=49$
$\frac{\sin\left(x\right)}{1+\sin\left(x\right)}-\frac{\sin\left(x\right)}{1-\sin\left(x\right)}$
$6x^5+12x$
$x'=x-5y+3$
$45.07-3.005$
$\frac{dy}{dx}=6x+5$
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