$60x+x^2=800$
$\int_0^{40}cos\:\frac{nt}{500}\:dt$
$-\:4\:\left[6\:+\:5\:-\:\left(3\:+\:2\right)\:-\:4\right]\:-\:3$
$\frac{1}{2}x+\frac{1}{3}x=5$
$\sqrt{a\sqrt{a}}$
$\left(4x+6y-3\right)dx+\left(6x-3y+1\right)dy=0$
$2x-5+3x-7x-10-2x$
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