$y'+3y=x+e^{\left(-2x\right)}$
$\int\sqrt{1+\left(144\left(x+3\right)\right)}dx$
$\int\sec^3\left(\frac{x}{3}\right)dx$
$\log2\left(3x-1\right)=-5$
$y'-56ty=0$
$\left(12x^3-3\right)$
$\left(3x\right)^{-\sqrt{x}}$
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