$9^2\infty9^{-12}$
$\left(4-6\right)\cdot5$
$\frac{dy}{dx}=\left(1+x\right)\left(y^2\right)$
$\frac{6^{11}}{6^{10}}$
$\lim_{x\to-4}\left(\frac{x-4}{x}\right)$
$\lim_{x\to\infty}\left(\frac{sinx\:\cdot\:x}{x^3+2x^2-x+1}\right)$
$\frac{7}{9}p-\frac{1}{4}<\frac{5}{8}p+\frac{2}{5}$
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