$\lim_{x\to0}\left(\frac{\sin\left(x\right)}{\ln\left(x+1\right)\cos\left(4x\right)}\right)$
$\frac{dy}{dt}-y=0$
$6r^2-6-5r$
$\frac{dy}{dx}=\frac{ye^{-3x}}{y^2e^{-y}+ycos\left(4y\right)}$
$\int\left(3x^2+7\right)in\:x\:dx$
$2x^{2-2x+1}$
$1-\sin^2$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!