$\frac{x^{3^3}-3^{3^3}}{x^3-3^3}$
$9\le9x+7$
$\frac{d^3y}{dx^3}y=\left(\frac{x^3}{x-1}\right)$
$25x^2+ab+4=0$
$3x^2-5x^2+52x+12$
$\frac{\cot\left(-t\right)+\tan\left(-t\right)}{\cot\left(t\right)}=-\sec^2\left(t\right)$
$8x-9=6\left(x-2\right)-3$
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