$\lim_{x\to\frac{\pi}{2}}\left(sec\left(3\right)cos\left(5x\right)\right)$

$y'-xy=1-x$

$\left(1\right)\left(x+2\right)^2$

$\frac{d}{dx}tan\left(5x+y\right)=5x$

$\frac{\left|\left(2x+1\right)^2\left(2x-1\right)^2\right|-\left(8x^2-2\right)^2}{16x^2}$

$\lim_{x\to0}\left(\frac{1}{x}-\tan\left(x\right)\right)\:$

$\left(y+xy\right)dx+x^2dy=0$