$16z^5-12^4+4y^2$
$9x^2-49$
$\:-16\:+\:20\:-\:8\:+\:2\:$
$\int x^2\left(5+\frac{x^3}{2}\right)^3dx$
$\sec\left(a\right)^4\:\sec\left(a\right)^2$
$\int\left(x^2-2x\right)\left(x^3-3x^2\right)^3dx$
$\left(30a\right)\left(-40b\right)\left(10a\right)\left(-20b\right)$
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