$2\left(6+5x\right)+3\left(x+1\right)>2\left(6x+4\right)$
$\lim_{x\to\infty}\left(\frac{11}{15x^2-6x+11}\right)$
$36x^2-27$
$21x-28<0$
$x^4-26x^2+225$
$\log_{40}\left(x\right)+\log_{40}\left(x-3\right)=1$
$6x+x^2=31$
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