$a^2-32+4$
$\frac{6}{\sqrt{25-x^2}}$
$\left(x^5+3y\right)dx-dy=0$
$\lim_{x\to2}\left(\left(x^{2}-x\right)\right)$
$\left(-7\right)\left(-5\right)\left(-4\right)$
$2x^2-12x-3=0$
$\left(x+6y\right)\left(x^2-6xy+36y^2\right)$
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